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21125_StringMatching

2022-5-16 18:18| 发布者: Hocassian| 查看: 48| 评论: 0|原作者: 肇庆学院ACM合集

摘要:

C:\Users\Administrator\Downloads\2019-10-12-10-14-3-89504868974700-Problem List-采集的数据-后羿采集器.html

Pro.ID

21125

Title

String Matching

Title链接

http://10.20.2.8/oj/exercise/problem?problem_id=21125

AC

Submit

123

Ratio

40.65%

时间&空间限制

Time Limit: 300/100 MS (Java/Others) Memory Limit: 20000/10000 K (Java/Others)

描述

It's easy to tell if two words are identical - just check the letters. But how do you tell if two words are almost identical? And how close is "almost"?
There are lots of techniques for approximate word matching. One is to determine the best substring match, which is the number of common letters when the words are compared letter-byletter.
The key to this approach is that the words can overlap in any way. For example, consider the words CAPILLARY and MARSUPIAL. One way to compare them is to overlay them:
CAPILLARY
MARSUPIAL
There is only one common letter (A). Better is the following overlay:

CAPILLARY
     MARSUPIAL

with two common letters (A and R), but the best is:

   CAPILLARY
MARSUPIAL

Which has three common letters (P, I and L).
The approximation measure appx(word1, word2) for two words is given by:
common letters * 2
-----------------------------
length(word1) + length(word2) Thus, for this example, appx(CAPILLARY, MARSUPIAL) = 6 / (9 + 9) = 1/3. Obviously, for any word W appx(W, W) = 1, which is a nice property, while words with no common letters have an appx value of 0.

输入

The input for your program will be a series of words, two per line, until the end-of-file flag of -1.
Using the above technique, you are to calculate appx() for the pair of words on the line and print the result.
The words will all be uppercase.

输出

Description

CAPILLARY
     MARSUPIAL

with two common letters (A and R), but the best is:

   CAPILLARY
MARSUPIAL

Input

Output

Print the value for appx() for each pair as a reduced fraction,Fractions reducing to zero or one should have no denominator.

Sample Input

CAR CART
TURKEY CHICKEN
MONEY POVERTY
ROUGH PESKY
A A
-1

Sample Output

appx(CAR,CART) = 6/7
appx(TURKEY,CHICKEN) = 4/13
appx(MONEY,POVERTY) = 1/3
appx(ROUGH,PESKY) = 0
appx(A,A) = 1

Source

Pacific Northwest 1999

样例输入

CAR CART
TURKEY CHICKEN
MONEY POVERTY
ROUGH PESKY
A A
-1

样例输出

appx(CAR,CART) = 6/7
appx(TURKEY,CHICKEN) = 4/13
appx(MONEY,POVERTY) = 1/3
appx(ROUGH,PESKY) = 0
appx(A,A) = 1

提示