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21892_S-Ni

2022-5-16 18:20| 发布者: Hocassian| 查看: 29| 评论: 0|原作者: 肇庆学院ACM合集

摘要:

C:\Users\Administrator\Downloads\2019-10-12-10-14-4-89505935769600-Problem List-采集的数据-后羿采集器.html

Pro.ID

21892

Title

S-Nim

Title链接

http://10.20.2.8/oj/exercise/problem?problem_id=21892

AC

Submit

Ratio

58.33%

时间&空间限制

Time Limit: 6000/2000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)

描述

Arthur and his sister Caroll have been playing a game called Nim for some time now. Nim is played as follows:

. The starting position has a number of heaps, all containing some, not necessarily equal, number of beads.

. The players take turns chosing a heap and removing a positivenumber of beads from it.

. The first player not able to make a move, loses.Arthur and Caroll really enjoyed playing this simple game until they

recently learned an easy way to always be able to find the best move:

. Xor the number of beads in the heaps in the current position (i.e. if we have 2, 4 and 7 the xor-sum will be 1 as 2 xor 4 xor 7 = 1).

. If the xor-sum is 0, too bad, you will lose.

. Otherwise, move such that the xor-sum becomes 0. This is alwayspossible.

It is quite easy to convince oneself that this works. Consider these facts:

. The player that takes the last bead wins.

. After the winning player's last move the xor-sum will be 0.

. The xor-sum will change after every move.

Which means that if you make sure that the xor-sum always is 0 when you have made your move, your opponent will never be able to win, and, thus, you will win.

Understandibly it is no fun to play a game when both players know how to play perfectly (ignorance is bliss). Fourtunately, Arthur and Caroll soon came up with a similar game, S-Nim, that seemed to solve this problem. Each player is now only allowed to remove a number of beads in some predefined set S, e.g. if we have S = {2, 5} each player is only allowed to remove 2 or 5 beads. Now it is not always possible to make the xor-sum 0 and, thus, the strategy above is useless. Or is it? Your job is to write a program that determines if a position of S-Nim is a losing or a winning position. A position is a winning position if there is at least one move to a losing position. A position is a losing position if there are no moves to a losing position. This means, as expected, that a position with no legal moves is a losing position.

输入

Input consists of a number of test cases. For each test case: The first line contains a number k (0 < k <= 100) describing the size of S, followed by k numbers si (0 < si <= 10000) describing S. The second line contains a number m (0 < m <= 100) describing the number of positions to evaluate. The next m lines each contain a number l (0 < l <= 100) describing the number of heaps and l numbers hi (0 < hi <= 10000) describing the number of beads in the heaps. The last test case is followed by a 0 on a line of its own.

输出

Description

Arthur and his sister Caroll have been playing a game called Nim for some time now. Nim is played as follows:

. The starting position has a number of heaps, all containing some, not necessarily equal, number of beads.

. The players take turns chosing a heap and removing a positivenumber of beads from it.

. The first player not able to make a move, loses.Arthur and Caroll really enjoyed playing this simple game until they

recently learned an easy way to always be able to find the best move:

. Xor the number of beads in the heaps in the current position (i.e. if we have 2, 4 and 7 the xor-sum will be 1 as 2 xor 4 xor 7 = 1).

. If the xor-sum is 0, too bad, you will lose.

. Otherwise, move such that the xor-sum becomes 0. This is alwayspossible.

It is quite easy to convince oneself that this works. Consider these facts:

. The player that takes the last bead wins.

. After the winning player's last move the xor-sum will be 0.

. The xor-sum will change after every move.

Which means that if you make sure that the xor-sum always is 0 when you have made your move, your opponent will never be able to win, and, thus, you will win.

Input

Output

For each position:

. If the described position is a winning position print a 'W'.

. If the described position is a losing position print an 'L'.

Print a newline after each test case.

Sample Input

2 2 5
3
2 5 12
3 2 4 7
4 2 3 7 12
5 1 2 3 4 5
3
2 5 12
3 2 4 7
4 2 3 7 12
0

Sample Output

LWW
WWL

Source

Norgesmesterskapet i Programmering 2004

样例输入

2 2 5
3
2 5 12
3 2 4 7
4 2 3 7 12
5 1 2 3 4 5
3
2 5 12
3 2 4 7
4 2 3 7 12
0

样例输出

LWW
WWL

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