Pro.ID21895 TitleLazy Evaluation Title链接http://10.20.2.8/oj/exercise/problem?problem_id=21895 AC0 Submit0 Ratio- 时间&空间限制描述Most of the programming languages used in practice perform strict-evaluation. When a function is called, the expressions passed in the function arguments (for instance a + b in f ( a + b, 3)) are evaluated first, and the resulting values are passed to the function. However, this is not the only way how expressions can be evaluated, and in fact, even such a mainstream language as C++ is sometimes performing lazy evaluation: the operators && and || evaluate only those arguments that are needed to determine the value of the expression. Pal Christian is now working on a comparative study of the performance of the lazy and strict evaluation. Pal wants to evaluate in both ways a set of expressions that follow this simplified syntax:
Expressions are evaluated according to the following simple rules:
The following built-in functions are available: add x y - sum of the constants x and y, sub x y - returns the value x - y, mult x y - product of x and y, div x y - integer division, and rem x y - remainder (same semantics as '/' and '%' in C, C++ or Java), true x y - always returns x, f alse x y - always returns y , eq x y - returns true if x and y is the same constant, otherwise returns f alse, gt x y - returns true if x is greater than y, otherwise returns f alse. User-defined functions are defined using the following syntax: f unction name arg1 . . . argN = body, where arg1 . . . argN are distinct words (up to 32 English lowercase letters), denoting the formal parameters of the function, and the body is an expression. The formal parameters can occur in the body of the function in place of constants or names. The function name and the formal parameters are separated by a single space. There is one space on both sides of the "=". Functions with zero (no) arguments are legal. Note that the formal parameters can overshadow the function names (i.e. op in definition of not in sample input overshadows the function name op), but each function must have a unique name. 输入The first part of the input contains (less than 1000) lines with one function definition each, followed by a single empty line. Forward references (that is, referring to functions defined later in the input) and recursion are legal. The second part of the input contains less than 1000 test expressions. Each test expression is an expresion occupying a single line. Function names and the arguments are always separated by a single space, but there are no extra spaces around parentheses (see sample input). There is an empty line after the last expression. Expressions are to be evaluated by both the lazy and the strict evaluation. You can assume that all function definitions and expressions are syntactically correct, and that the arithmetic built-in functions (add, sub, mult, div, rem, eq, gt) will always be called with integers only, and no division by 0 occurs. Overflows outside the 32-bit integer range are legal and do not require any special treatment (just use the value produced by C, C++, or Java operators +, -, *, /, or %). In strict evaluation, built-in functions evaluate all their arguments too. In lazy evaluation, arithmetic built-in functions always evaluate all their arguments. All lines on the input contain no more than 255 characters including spaces. 输出Description Most of the programming languages used in practice perform strict-evaluation. When a function is called, the expressions passed in the function arguments (for instance a + b in f ( a + b, 3)) are evaluated first, and the resulting values are passed to the function. However, this is not the only way how expressions can be evaluated, and in fact, even such a mainstream language as C++ is sometimes performing lazy evaluation: the operators && and || evaluate only those arguments that are needed to determine the value of the expression. Pal Christian is now working on a comparative study of the performance of the lazy and strict evaluation. Pal wants to evaluate in both ways a set of expressions that follow this simplified syntax:
Expressions are evaluated according to the following simple rules:
The following built-in functions are available: add x y - sum of the constants x and y, sub x y - returns the value x - y, mult x y - product of x and y, div x y - integer division, and rem x y - remainder (same semantics as '/' and '%' in C, C++ or Java), true x y - always returns x, f alse x y - always returns y , eq x y - returns true if x and y is the same constant, otherwise returns f alse, gt x y - returns true if x is greater than y, otherwise returns f alse. User-defined functions are defined using the following syntax: f unction name arg1 . . . argN = body, where arg1 . . . argN are distinct words (up to 32 English lowercase letters), denoting the formal parameters of the function, and the body is an expression. The formal parameters can occur in the body of the function in place of constants or names. The function name and the formal parameters are separated by a single space. There is one space on both sides of the "=". Functions with zero (no) arguments are legal. Note that the formal parameters can overshadow the function names (i.e. op in definition of not in sample input overshadows the function name op), but each function must have a unique name. Input The first part of the input contains (less than 1000) lines with one function definition each, followed by a single empty line. Forward references (that is, referring to functions defined later in the input) and recursion are legal. The second part of the input contains less than 1000 test expressions. Each test expression is an expresion occupying a single line. Function names and the arguments are always separated by a single space, but there are no extra spaces around parentheses (see sample input). There is an empty line after the last expression. Expressions are to be evaluated by both the lazy and the strict evaluation. You can assume that all function definitions and expressions are syntactically correct, and that the arithmetic built-in functions (add, sub, mult, div, rem, eq, gt) will always be called with integers only, and no division by 0 occurs. Overflows outside the 32-bit integer range are legal and do not require any special treatment (just use the value produced by C, C++, or Java operators +, -, *, /, or %). In strict evaluation, built-in functions evaluate all their arguments too. In lazy evaluation, arithmetic built-in functions always evaluate all their arguments. All lines on the input contain no more than 255 characters including spaces. Output The program should produce a table in exactly the following format: operator lazy evaluation strict evaluation add addlazy addstrict sub sublazy substrict mult multlazy multstrict div divlazy divstrict rem remlazy remstrictwhere each oplazy is an integer -- how many times op has been executed in lazy evaluation of all expressions, and op strict is the number of evaluations of op in strict evaluation. Spaces can occur arbitrarily. If the evaluation of a test expression does not terminate after a total of 2345 function evaluations, you can assume that it is in an infinite loop, the program should skip that expression, and do not count it into the totals (omit counting operations both in lazy and strict evaluation of this expression). Sample Input if cond truepart elsepart = (cond truepart elsepart)
fact x = (facta x 1)
facta x a = (if (eq x 0) a (facta (sub x 1) (mult a x)))
and x y = (x y false)
ident x = x
two = 2
op op x = ((if (eq op 1) add sub) op x)
not op = (op false true)
sum n = (suma n 0)
suma n a = (((gt n 1) suma false) (sub n 1) (add a n))
(true (add 1 2) (mult 1 2))
5
true
(and (gt (op (sub 2 1) 1) 5) (eq (two) (op 1 1)))
(false (sub 1 2) (sum 4))
((eq (true 1 2) (false 2 1)) (add 1 2) (sub 1 2))
(fact 3) Sample Output operator lazy_evaluation strict_evaluation
add 7 8
sub 4 7
mult 0 1
div 0 0
rem 0 0 Source 样例输入if cond truepart elsepart = (cond truepart elsepart)
fact x = (facta x 1)
facta x a = (if (eq x 0) a (facta (sub x 1) (mult a x)))
and x y = (x y false)
ident x = x
two = 2
op op x = ((if (eq op 1) add sub) op x)
not op = (op false true)
sum n = (suma n 0)
suma n a = (((gt n 1) suma false) (sub n 1) (add a n))
(true (add 1 2) (mult 1 2))
5
true
(and (gt (op (sub 2 1) 1) 5) (eq (two) (op 1 1)))
(false (sub 1 2) (sum 4))
((eq (true 1 2) (false 2 1)) (add 1 2) (sub 1 2))
(fact 3) 样例输出operator lazy_evaluation strict_evaluation
add 7 8
sub 4 7
mult 0 1
div 0 0
rem 0 0 作者 |