22366_Basicremains

2022-5-16 18:21| 发布者: Hocassian| 查看: 28| 评论: 0|原作者: 肇庆学院ACM合集

摘要:
C:\Users\Administrator\Downloads\2019-10-12-10-14-5-89506360477700-Problem List-采集的数据-后羿采集器.html

Pro.ID

22366

Title

Basic remains

Title链接

http://10.20.2.8/oj/exercise/problem?problem_id=22366

AC

2

Submit

3

Ratio

66.67%

时间&空间限制

  • Time Limit: 1200/400 MS (Java/Others)     Memory Limit: 131072/65536 K (Java/Others)
  • 描述

    Given a base b and two non-negative base b integers p and m, compute p mod m and print the result as a base b integer. p mod m is defined as the smallest non-negative integer k such that p = a*m + k for some integer a.

    输入

    Input consists of a number of cases. Each case is represented by a line containing three unsigned integers. The first, b, is a decimal number between 2 and 10. The second, p, contains up to 1000 digits between 0 and b-1. The third, m, contains up to 9 digits between 0 and b-1. The last case is followed by a line containing 0.

    输出

    Description
    Given a base b and two non-negative base b integers p and m, compute p mod m and print the result as a base b integer. p mod m is defined as the smallest non-negative integer k such that p = a*m + k for some integer a.
    Input
    Input consists of a number of cases. Each case is represented by a line containing three unsigned integers. The first, b, is a decimal number between 2 and 10. The second, p, contains up to 1000 digits between 0 and b-1. The third, m, contains up to 9 digits between 0 and b-1. The last case is followed by a line containing 0.
    Output
    For each test case, print a line giving p mod m as a base-b integer.
    Sample Input
    2 1100 101
    10 123456789123456789123456789 1000
    0
    Sample Output
    10
    789
    Source

    样例输入

    2 1100 101
    10 123456789123456789123456789 1000
    0

    样例输出

    10
    789

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